Our ncert solutions for Exercise 8.2 Class 11 maths 8. Binomial Theorem - ncert solutions - Toppers Study is the best material for English Medium students cbse board and other state boards students.

# Exercise 8.2 Class 11 maths 8. Binomial Theorem - ncert solutions - Toppers Study

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## Exercise 8.2 Class 11 maths 8. Binomial Theorem - ncert solutions - Toppers Study

CBSE board students who preparing for **class 11 ncert solutions maths and Mathematics** solved exercise **chapter 8. Binomial Theorem** available and this helps in upcoming exams
2023-2024.

### You can Find Mathematics solution Class 11 Chapter 8. Binomial Theorem

- All Chapter review quick revision notes for chapter 8. Binomial Theorem Class 11
- NCERT Solutions And Textual questions Answers Class 11 Mathematics
- Extra NCERT Book questions Answers Class 11 Mathematics
- Importatnt key points with additional Assignment and questions bank solved.

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### Exercise 8.2 class 11 Mathematics Chapter 8. Binomial Theorem

Sure! The following topics will be covered in this article

- Exercise 8.2 Class 11 Maths 8. Binomial Theorem - Ncert Solutions - Toppers Study
- Class 11 Ncert Solutions
- Solution Chapter 8. Binomial Theorem Class 11
- Solutions Class 11
- Chapter 8. Binomial Theorem Exercise 8.2 Class 11

## 8. Binomial Theorem

### | Exercise 8.2 |

## Exercise 8.2 Class 11 maths 8. Binomial Theorem - ncert solutions - Toppers Study

Exercise 8.2

**Find the coefficient of **

**Q1. x ^{5} in (x + 3)^{8} **

**Solution: **

(x + 3)^{8}

General term ^{n}C_{r }a^{n-r }b^{r }

n = 8, then

^{8}C_{r} x^{8-r} 3^{r} ⇒ x^{5} = x^{8-r}

5 = 8-r

∴ r = 8-5 = 3

^{8}C_{3} x^{8-3} 3^{3} = ^{8}C_{3} x^{5} 3^{3}

Coefficient in x^{5} = ^{8}C_{3 }3^{3}

= 1512

**Q2. a ^{5}b^{7} in (a-2b)^{12} **

**Solution: **

(a-2b)^{12}

General Term T_{r+1} = ^{n}C_{r }a^{n-r }b^{r}

^{12}C_{r} a^{12-r }b^{r}

∴12 – r = 5 ⇒ r = 12 – 5 = 7

a^{5}b^{7} is 8 term

T_{8} = ^{12}C_{7 }a^{5 }b^{7}

= ^{12}C_{7 }a^{5} (-2b)^{7}

= - 72 × 11 × 2^{7}

= - 72 × 11 × 128 = - 101376

**Write the general term in the expansion of**

**Q3. (x ^{2} - y)^{6}**

Solution:

General term of **(x ^{2} - y)^{6}**

n = 6, a = x^{2}, b = (-y)

General Term T_{r +1} = ^{n}C_{r }a^{n-r }b^{r}

= ^{6}C_{r}_{ }_{(x2)6}^{-r (-y)}^{r}

=

##### Other Pages of this Chapter: 8. Binomial Theorem

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