Our ncert solutions for Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study is the best material for English Medium students cbse board and other state boards students.

# Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study

Topper Study classes prepares ncert solutions on practical base problems and comes out with the best result that helps the students and teachers as well as tutors and so many ecademic coaching classes that they need in practical life. Our ncert solutions for Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study is the best material for English Medium students cbse board and other state boards students.

## Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study

CBSE board students who preparing for **class 11 ncert solutions maths and Mathematics** solved exercise **chapter 11. Conic Sections** available and this helps in upcoming exams
2022-2023.

### You can Find Mathematics solution Class 11 Chapter 11. Conic Sections

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### Exercise 11.2 class 11 Mathematics Chapter 11. Conic Sections

## 11. Conic Sections

### | Exercise 11.2 |

## Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study

## Exercise 11.2 (Conic Sections)

**Q1. Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for y ^{2} = 12x.**

**Solution:**

The given equation is y

^{2}= 12x.

Here, the coefficient of x is positive. Hence, the parabola opens towards the right.

On comparing this equation with y

^{2}= 4ax, we obtain

4a = 12 ⇒ a = 3

∴ Coordinates of the focus = (a, 0) = (3, 0)

Since the given equation involves y

^{2}, the axis of the parabola is the x-axis.

Equation of direcctrix, x = –a i.e., x = – 3 i.e., x + 3 = 0

Length of latus rectum = 4a = 4 × 3 = 12

**Q3. Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for y2 = – 8x.**

**Solution: **

The given equation is y^{2} = –8x.

Here, the coefficient of x is negative. Hence, the parabola opens towards the left.

On comparing this equation with y^{2} = –4ax, we obtain

–4a = –8 ⇒ a = 2

∴Coordinates of the focus = (–a, 0) = (–2, 0)

Since the given equation involves y^{2}, the axis of the parabola is the x-axis.

Equation of directrix, x = a i.e., x = 2

Length of latus rectum = 4a = 8

**Q4. Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for x ^{2} = – 16y.**

**Solution:**

The given equation is x

^{2}= –16y.

Here, the coefficient of y is negative. Hence, the parabola opens downwards.

On comparing this equation with x

^{2}= – 4ay, we obtain

–4a = –16 ⇒ a = 4

∴Coordinates of the focus = (0, –a) = (0, –4)

Since the given equation involves x

^{2}, the axis of the parabola is the y-axis.

Equation of directrix, y = a i.e., y = 4

Length of latus rectum = 4a = 16

**Q7. Find the equation of the parabola that satisfies the following conditions: Focus (6, 0); directrix x = –6.**

**Solution:**

Focus (6, 0); directrix, x = –6

Since the focus lies on the x-axis, the x-axis is the axis of the parabola.

Therefore, the equation of the parabola is either of the form y^{2} = 4ax or

y^{2} = – 4ax.

It is also seen that the directrix, x = – 6 is to the left of the y-axis, while the focus (6, 0) is to the right of the y-axis.

Hence, the parabola is of the form y^{2} = 4ax.

Here, a = 6

Thus, the equation of the parabola is y^{2} = 24x.

##### Other Pages of this Chapter: 11. Conic Sections

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