Study Materials: ncert solutions

Our ncert solutions for Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study is the best material for English Medium students cbse board and other state boards students.

Solutions ⇒ Class 11th ⇒ Mathematics ⇒ 11. Conic Sections

Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study

Topper Study classes prepares ncert solutions on practical base problems and comes out with the best result that helps the students and teachers as well as tutors and so many ecademic coaching classes that they need in practical life. Our ncert solutions for Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study is the best material for English Medium students cbse board and other state boards students.

Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study

CBSE board students who preparing for class 11 ncert solutions maths and Mathematics solved exercise chapter 11. Conic Sections available and this helps in upcoming exams 2024-2025.

You can Find Mathematics solution Class 11 Chapter 11. Conic Sections

All Chapter review quick revision notes for chapter 11. Conic Sections Class 11
NCERT Solutions And Textual questions Answers Class 11 Mathematics
Extra NCERT Book questions Answers Class 11 Mathematics
Importatnt key points with additional Assignment and questions bank solved.

NCERT Solutions do not only help you to cover your syllabus but also will give to textual support in exams 2024-2025 to complete exercise 11.2 maths class 11 chapter 11 in english medium. So revise and practice these all cbse study materials like class 11 maths chapter 11.2 in english ncert book. Also ensure to repractice all syllabus within time or before board exams for ncert class 11 maths ex 11.2 in english.

See all solutions for class 11 maths chapter 11 exercise 11 in english medium solved questions with answers.

Exercise 11.2 class 11 Mathematics Chapter 11. Conic Sections

Sure! The following topics will be covered in this article

Exercise 11.2 Class 11 Maths 11. Conic Sections - Ncert Solutions - Toppers Study
Class 11 Ncert Solutions
Solution Chapter 11. Conic Sections Class 11
Solutions Class 11
Chapter 11. Conic Sections Exercise 11.2 Class 11

Notice

/home/atpeduca/public_html/toppersstudy.com/view-home.php

123

11. Conic Sections

| Exercise 11.2 |

Exercise 11.2 Class 11 maths 11. Conic Sections - ncert solutions - Toppers Study

Exercise 11.2 (Conic Sections)

Q1. Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for y² = 12x.
Solution:
The given equation is y² = 12x.
Here, the coefficient of x is positive. Hence, the parabola opens towards the right.
On comparing this equation with y² = 4ax, we obtain
4a = 12 ⇒ a = 3
∴ Coordinates of the focus = (a, 0) = (3, 0)
Since the given equation involves y², the axis of the parabola is the x-axis.
Equation of direcctrix, x = –a i.e., x = – 3 i.e., x + 3 = 0
Length of latus rectum = 4a = 4 × 3 = 12

Q3. Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for y2 = – 8x.
Solution:
The given equation is y² = –8x.
Here, the coefficient of x is negative. Hence, the parabola opens towards the left.

On comparing this equation with y² = –4ax, we obtain
–4a = –8 ⇒ a = 2
∴Coordinates of the focus = (–a, 0) = (–2, 0)
Since the given equation involves y², the axis of the parabola is the x-axis.
Equation of directrix, x = a i.e., x = 2
Length of latus rectum = 4a = 8

Q4. Find the coordinates of the focus, axis of the parabola, the equation of directrix and the length of the latus rectum for x² = – 16y.
Solution:
The given equation is x² = –16y.
Here, the coefficient of y is negative. Hence, the parabola opens downwards.
On comparing this equation with x² = – 4ay, we obtain
–4a = –16 ⇒ a = 4
∴Coordinates of the focus = (0, –a) = (0, –4)
Since the given equation involves x², the axis of the parabola is the y-axis.
Equation of directrix, y = a i.e., y = 4
Length of latus rectum = 4a = 16

Q7. Find the equation of the parabola that satisfies the following conditions: Focus (6, 0); directrix x = –6.
Solution:
Focus (6, 0); directrix, x = –6
Since the focus lies on the x-axis, the x-axis is the axis of the parabola.
Therefore, the equation of the parabola is either of the form y² = 4ax or
y² = – 4ax.
It is also seen that the directrix, x = – 6 is to the left of the y-axis, while the focus (6, 0) is to the right of the y-axis.
Hence, the parabola is of the form y² = 4ax.
Here, a = 6
Thus, the equation of the parabola is y² = 24x.

Other Pages of this Chapter: 11. Conic Sections

1. Chapter 11. Conic Sections | Exercise 11.1

2. Chapter 11. Conic Sections | Exercise 11.2

3. Chapter 11. Conic Sections | Exercise 11.3

4. Chapter 11. Conic Sections | Exercise 11.4

5. Chapter 11. Conic Sections | Miscellaneous Exercise on Chapter - 11

Select Your CBSE Classes

Important Study materials for classes 06, 07, 08,09,10, 11 and 12. Like CBSE Notes, Notes for Science, Notes for maths, Notes for Social Science, Notes for Accountancy, Notes for Economics, Notes for political Science, Noes for History, Notes For Bussiness Study, Physical Educations, Sample Papers, Test Papers, Mock Test Papers, Support Materials and Books.