Our ncert solutions for Solutions 2. Whole Numbers - Exercise 2.2 | Class 6 Mathematics - Toppers Study is the best material for English Medium students cbse board and other state boards students.

# Solutions 2. Whole Numbers - Exercise 2.2 | Class 6 Mathematics - Toppers Study

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## 2. Whole Numbers

### | Exercise 2.2 |

## Solutions 2. Whole Numbers - Exercise 2.2 | Class 6 Mathematics - Toppers Study

#### Exercise-2.2

**Q1. Find the sum by suitable rearrangement:**

**(a) 837 + 208 + 363**

**Solution:** 837 + 208 + 363

= (837 + 208) + 363

= 1045 + 363

= 1408

**Or Second Method **

= 837 + 363 + 208

= (837 + 363) + 208

= 1200 + 208

= 1408

**(b) 1962 + 453 + 1538 + 647**

**Solution:** 1962 + 453 + 1538 + 6477

= (1962 + 453) + (1538 + 647)

= 2415 + 2185

= 4600

**Or Second Method **

= 1962 + 453 + 1538 + 6477

= (1538 + 1962) + (453 + 647)

= 3500 + 1100

= 4600

**Q2. Find the product by suitable rearrangement:**

**(a) 2 × 1768 × 50**

**(b) 4 × 166 × 25**

**(c) 8 × 291 × 125**

**(d) 625 × 279 × 16**

**(e) 285 × 5 × 60**

**(f) 125 × 40 × 8 × 25**

**Solution: **

**(a) 2 x 1768 x 50 **

**Solution:**

2 x 50 x 1768

= (2 x 50) x 1768

= 100 x 1768

= 176800

**(b) 4 x 166 x 25**

**Solution: **

4 x 25 x 166

= (4 x 25) x 166

= 100 x 166

= 16600

**(c) 8 x 291 x 125**

**Solution:**

8 x 125 x 291

= 1000 x 291`

= 291000

**(d) 125 x 40 x 8 x 25**

**Solution:**

125 x 8 x 40 x 25

= (125 x 8) x (40 x 25)

= 1000 x 1000

= 1000000

**(e) 285 × 5 × 60**

**Solution:**

285 × 5 × 60

= 285 × (5 × 60)

= 285 × 300

= 85500

**(f) 125 × 40 × 8 × 25**

**Solution: **

125 × 40 × 8 × 25

= (125 × 8) × (40 × 25)

= 1000 × 1000

= 1000000

**Q3. Find the value of the following:**

**(a) 297 × 17 + 297 × 3**

**Solution:**

297 x (17 + 3)

= 297 x 20

= 5940

**(b) 54279 × 92 + 8 × 54279**

**Solution:**

54279 x (92 + 8)

= 54279 x 100

= 5427900

**(c) 81265 × 169 – 81265 × 69**

**Solution: **

81265 × 169 – 81265 × 69

= 81265 (169 – 69)

= 81265 (100)

= 8126500

**(d) 3845 × 5 × 782 + 769 × 25 × 218**

**Solution: **

3845 × 5 × 782 + 769 × 25 × 218

= 3845 × 5 × 782 + 769 × 5 × 5 × 218

= **3845 ****× 5 **× 782 + **3845 × 5** × 218

= 3845 × 5 (782 + 218)

= 19225 × 1000

= 19225000

**Q4. Find the product using suitable properties.**

**(a) 738 × 103**

**(b) 854 × 102**

**(c) 258 × 1008**

**(d) 1005 × 168**

**Solution: **

**(a) 738 × 103**

= 738 (100 + 3)

= 738 × 100 + 738 × 3

= 73800 + 2214

= 76014

**Solution:**

**(b) 854 × 102**

= 854(100 + 2)

= 854 × 100 + 854 × 2

= 85400 + 1708

= 87108

**Solution: **

**(c) 258 × 1008**

= 258(1000 + 8)

= 258 × 1000 + 258 × 8

= 258000 + 2064

= 260064

**Solution:**

**(d) 1005 × 168**

= (1000 + 5) x 168

= 1000 x 168 + 5 x 168

= 168000 + 840

= 168840

**5. A taxidriver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs Rs 44 per litre, how much did he spend in all on petrol?**

**Solution:** Taxi driver filled his car petrol tank on Monday = 40 L

He filled the petrol tank on Tuesday = 50 L

The petrol costs per liter = 44 Rs

He spend in all on petrol = (40 + 50) x 44

= 90 x 44

= 3960 Rs

**6. A vendor supplies 32 liters of milk to a hotel in the morning and 68 liters of milk in the evening. If the milk costs Rs 15 per liter, how much money is due to the vendor per day?**

**Solution:** A vendor supplies milk to a hotel in the morning = 32 liters

=> A vendor supplies milk to a hotel in the evening = 68 liters

=> The cost of milk per liter = Rs 15

**7. Match the following: **

**Solution: **

(i) ----------- (c)

(ii) ---------- (a)

(iii) ---------- (b)

##### Other Pages of this Chapter: 2. Whole Numbers

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