Our ncert solutions for Exercise 2.2 Class 6 maths 2. Whole Numbers - ncert solutions - Toppers Study is the best material for English Medium students cbse board and other state boards students.

# Exercise 2.2 Class 6 maths 2. Whole Numbers - ncert solutions - Toppers Study

Topper Study classes prepares ncert solutions on practical base problems and comes out with the best result that helps the students and teachers as well as tutors and so many ecademic coaching classes that they need in practical life. Our ncert solutions for Exercise 2.2 Class 6 maths 2. Whole Numbers - ncert solutions - Toppers Study is the best material for English Medium students cbse board and other state boards students.

## Exercise 2.2 Class 6 maths 2. Whole Numbers - ncert solutions - Toppers Study

CBSE board students who preparing for **class 6 ncert solutions maths and Mathematics** solved exercise **chapter 2. Whole Numbers** available and this helps in upcoming exams
2023-2024.

### You can Find Mathematics solution Class 6 Chapter 2. Whole Numbers

- All Chapter review quick revision notes for chapter 2. Whole Numbers Class 6
- NCERT Solutions And Textual questions Answers Class 6 Mathematics
- Extra NCERT Book questions Answers Class 6 Mathematics
- Importatnt key points with additional Assignment and questions bank solved.

NCERT Solutions do not only help you to cover your syllabus but also will give to textual support in exams 2023-2024 to complete **exercise 2.2 maths class 6 chapter 2** in english medium. So revise and practice these all cbse study materials like class 6 maths chapter 2.2 in english ncert book. Also ensure to repractice all syllabus within time or before board exams for ncert class 6 maths ex 2.2 in english.

See all solutions for class 6 maths chapter 2 exercise 2 in english medium solved questions with answers.

### Exercise 2.2 class 6 Mathematics Chapter 2. Whole Numbers

Sure! The following topics will be covered in this article

- Exercise 2.2 Class 6 Maths 2. Whole Numbers - Ncert Solutions - Toppers Study
- Class 6 Ncert Solutions
- Solution Chapter 2. Whole Numbers Class 6
- Solutions Class 6
- Chapter 2. Whole Numbers Exercise 2.2 Class 6

## 2. Whole Numbers

### | Exercise 2.2 |

## Exercise 2.2 Class 6 maths 2. Whole Numbers - ncert solutions - Toppers Study

#### Exercise-2.2

**Q1. Find the sum by suitable rearrangement:**

**(a) 837 + 208 + 363**

**Solution:** 837 + 208 + 363

= (837 + 208) + 363

= 1045 + 363

= 1408

**Or Second Method **

= 837 + 363 + 208

= (837 + 363) + 208

= 1200 + 208

= 1408

**(b) 1962 + 453 + 1538 + 647**

**Solution:** 1962 + 453 + 1538 + 6477

= (1962 + 453) + (1538 + 647)

= 2415 + 2185

= 4600

**Or Second Method **

= 1962 + 453 + 1538 + 6477

= (1538 + 1962) + (453 + 647)

= 3500 + 1100

= 4600

**Q2. Find the product by suitable rearrangement:**

**(a) 2 × 1768 × 50**

**(b) 4 × 166 × 25**

**(c) 8 × 291 × 125**

**(d) 625 × 279 × 16**

**(e) 285 × 5 × 60**

**(f) 125 × 40 × 8 × 25**

**Solution: **

**(a) 2 x 1768 x 50 **

**Solution:**

2 x 50 x 1768

= (2 x 50) x 1768

= 100 x 1768

= 176800

**(b) 4 x 166 x 25**

**Solution: **

4 x 25 x 166

= (4 x 25) x 166

= 100 x 166

= 16600

**(c) 8 x 291 x 125**

**Solution:**

8 x 125 x 291

= 1000 x 291`

= 291000

**(d) 125 x 40 x 8 x 25**

**Solution:**

125 x 8 x 40 x 25

= (125 x 8) x (40 x 25)

= 1000 x 1000

= 1000000

**(e) 285 × 5 × 60**

**Solution:**

285 × 5 × 60

= 285 × (5 × 60)

= 285 × 300

= 85500

**(f) 125 × 40 × 8 × 25**

**Solution: **

125 × 40 × 8 × 25

= (125 × 8) × (40 × 25)

= 1000 × 1000

= 1000000

**Q3. Find the value of the following:**

**(a) 297 × 17 + 297 × 3**

**Solution:**

297 x (17 + 3)

= 297 x 20

= 5940

**(b) 54279 × 92 + 8 × 54279**

**Solution:**

54279 x (92 + 8)

= 54279 x 100

= 5427900

**(c) 81265 × 169 – 81265 × 69**

**Solution: **

81265 × 169 – 81265 × 69

= 81265 (169 – 69)

= 81265 (100)

= 8126500

**(d) 3845 × 5 × 782 + 769 × 25 × 218**

**Solution: **

3845 × 5 × 782 + 769 × 25 × 218

= 3845 × 5 × 782 + 769 × 5 × 5 × 218

= **3845 ****× 5 **× 782 + **3845 × 5** × 218

= 3845 × 5 (782 + 218)

= 19225 × 1000

= 19225000

**Q4. Find the product using suitable properties.**

**(a) 738 × 103**

**(b) 854 × 102**

**(c) 258 × 1008**

**(d) 1005 × 168**

**Solution: **

**(a) 738 × 103**

= 738 (100 + 3)

= 738 × 100 + 738 × 3

= 73800 + 2214

= 76014

**Solution:**

**(b) 854 × 102**

= 854(100 + 2)

= 854 × 100 + 854 × 2

= 85400 + 1708

= 87108

**Solution: **

**(c) 258 × 1008**

= 258(1000 + 8)

= 258 × 1000 + 258 × 8

= 258000 + 2064

= 260064

**Solution:**

**(d) 1005 × 168**

= (1000 + 5) x 168

= 1000 x 168 + 5 x 168

= 168000 + 840

= 168840

**5. A taxidriver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs Rs 44 per litre, how much did he spend in all on petrol?**

**Solution:** Taxi driver filled his car petrol tank on Monday = 40 L

He filled the petrol tank on Tuesday = 50 L

The petrol costs per liter = 44 Rs

He spend in all on petrol = (40 + 50) x 44

= 90 x 44

= 3960 Rs

**6. A vendor supplies 32 liters of milk to a hotel in the morning and 68 liters of milk in the evening. If the milk costs Rs 15 per liter, how much money is due to the vendor per day?**

**Solution:** A vendor supplies milk to a hotel in the morning = 32 liters

=> A vendor supplies milk to a hotel in the evening = 68 liters

=> The cost of milk per liter = Rs 15

**7. Match the following: **

**Solution: **

(i) ----------- (c)

(ii) ---------- (a)

(iii) ---------- (b)

##### Other Pages of this Chapter: 2. Whole Numbers

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