Study Materials: ncert solutions

Our ncert solutions for Exercise 2.2 Class 9 maths 2. Polynomials - ncert solutions - Toppers Study is the best material for English Medium students cbse board and other state boards students.

Solutions ⇒ Class 9th ⇒ Mathematics ⇒ 2. Polynomials

Exercise 2.2 Class 9 maths 2. Polynomials - ncert solutions - Toppers Study

Topper Study classes prepares ncert solutions on practical base problems and comes out with the best result that helps the students and teachers as well as tutors and so many ecademic coaching classes that they need in practical life. Our ncert solutions for Exercise 2.2 Class 9 maths 2. Polynomials - ncert solutions - Toppers Study is the best material for English Medium students cbse board and other state boards students.

Exercise 2.2 Class 9 maths 2. Polynomials - ncert solutions - Toppers Study

CBSE board students who preparing for class 9 ncert solutions maths and Mathematics solved exercise chapter 2. Polynomials available and this helps in upcoming exams 2024-2025.

You can Find Mathematics solution Class 9 Chapter 2. Polynomials

  • All Chapter review quick revision notes for chapter 2. Polynomials Class 9
  • NCERT Solutions And Textual questions Answers Class 9 Mathematics
  • Extra NCERT Book questions Answers Class 9 Mathematics
  • Importatnt key points with additional Assignment and questions bank solved.

NCERT Solutions do not only help you to cover your syllabus but also will give to textual support in exams 2024-2025 to complete exercise 2.2 maths class 9 chapter 2 in english medium. So revise and practice these all cbse study materials like class 9 maths chapter 2.2 in english ncert book. Also ensure to repractice all syllabus within time or before board exams for ncert class 9 maths ex 2.2 in english.

See all solutions for class 9 maths chapter 2 exercise 2 in english medium solved questions with answers.

Exercise 2.2 class 9 Mathematics Chapter 2. Polynomials

Sure! The following topics will be covered in this article

  • Exercise 2.2 Class 9 Maths 2. Polynomials - Ncert Solutions - Toppers Study
  • Class 9 Ncert Solutions
  • Solution Chapter 2. Polynomials Class 9
  • Solutions Class 9
  • Chapter 2. Polynomials Exercise 2.2 Class 9

  • Notice: Undefined offset: 5 in /home/atpeduca/public_html/toppersstudy.com/view-home.php on line 123

2. Polynomials

| Exercise 2.2 |

Exercise 2.2 Class 9 maths 2. Polynomials - ncert solutions - Toppers Study


2. Polynomials


Exercise 2.2

Q1. Find the value of the polynomial 5x – 4x2 + 3 at

(i) x = 0 (ii) x = –1 (iii) x = 2

Solution:

(i) p(x) = 5x - 4x2 + 3

The value of the polynomial p(x) at x = 0 is given by

P(0) = 5(0) - 4(0)2 + 3

       = 0 - 0 + 3

       = 3

(ii) p(x) = 5x - 4x2 + 3

The value of the polynomial p(x) at x = 1 is given by

P(1) = 5(1) - 4(1)2 + 3

        = 5 - 4 + 3

        = 4

(iii) p(x) = 5x - 4x2 + 3

The value of the polynomial p(x) at x = 2 is given by

P(2) = 5(2) - 4(2)2 + 3

       = 10 -16 + 3

       = - 9

Q2.Find p(0), p(1) and p(2) for each of the following polynomials:

(i)  p(y) = y2 – y + 1

(ii) p(t) = 2 + t + 2t 2 – t 3

(iii) p(x) = x3

(iv) p(x) = (x – 1) (x + 1)

Solution:

(i) p(y) = y2 - y + 1

    P(0) = (0)2- 0 + 1

            =1

  P(1) = (1)2- 1 + 1

          = 1 - 1 + 1

          = 1

P(2) = (2)2- 2 + 1 = 4 - 2 + 1 = 3

(ii) p(t) = 2 + t + 2t2- t3

     P(0) = 2 + 0 + 2(0)2- (0)3

            =2

   P(1) = 2 + 1 + 2(1)2 - (1)3

            = 4

   P(2) = 2 + 2 + 2(2)2- (2)3

            = 4 + 8 - 8

            = 4

(iii) p(x) = x3

       P(0)=(0)3 =0

       P(1)=(1)3 =1

       P(2)=(2)3=8

(iv)p(x) = (x – 1) (x + 1)

       P(0)= (0-1) (0+1)=(-1) (1) =-1

       P(1)= (1-1) (1+1) =0(1)  =0

       P(2)= (2-1) (2+1)=1(3)  =3 

Q3. Verify whether the following are zeroes of the polynomial, indicated against them.

Solution:  

Q4. Find the zero of the polynomial in each of the following cases: 

(i)  P(x) = x + 5                                

(ii) P(x) = x 5                           

(iii) Px) = 2x + 5                              

(iv) P(x) = 3x 2                          

(v) P(x) = 3x                                    

(vi) P(x) = ax, a  0

Solution (i) :

(i)   P(x) = x + 5

      x + 5 = 0

     ⇒ x = - 5 

The zero of the polynomial is - 5. 

 Solution (ii) :

 (ii) P(x) = x  5

       x  5  = 0

     ⇒ x = 5

 The zero of the polynomial is  5.

 

The zero of the polynomial is - 5/2.

(iv)  P(x) = 3x - 2

       3x - 2 = 0

              

The zero of the polynomial is 2/3.

  

Select Your CBSE Classes

Important Study materials for classes 06, 07, 08,09,10, 11 and 12. Like CBSE Notes, Notes for Science, Notes for maths, Notes for Social Science, Notes for Accountancy, Notes for Economics, Notes for political Science, Noes for History, Notes For Bussiness Study, Physical Educations, Sample Papers, Test Papers, Mock Test Papers, Support Materials and Books.