Our ncert solutions for Exercise 2.2 Class 10 maths 2. Polynomials - ncert solutions - Toppers Study is the best material for English Medium students cbse board and other state boards students.

# Exercise 2.2 Class 10 maths 2. Polynomials - ncert solutions - Toppers Study

Topper Study classes prepares ncert solutions on practical base problems and comes out with the best result that helps the students and teachers as well as tutors and so many ecademic coaching classes that they need in practical life. Our ncert solutions for Exercise 2.2 Class 10 maths 2. Polynomials - ncert solutions - Toppers Study is the best material for English Medium students cbse board and other state boards students.

## Exercise 2.2 Class 10 maths 2. Polynomials - ncert solutions - Toppers Study

CBSE board students who preparing for **class 10 ncert solutions maths and Mathematics** solved exercise **chapter 2. Polynomials** available and this helps in upcoming exams
2022-2023.

### You can Find Mathematics solution Class 10 Chapter 2. Polynomials

- All Chapter review quick revision notes for chapter 2. Polynomials Class 10
- NCERT Solutions And Textual questions Answers
- Extra NCERT Book questions Answers
- Importatnt key points with additional Assignment and questions bank solved.

NCERT Solutions do not only help you to cover your syllabus but also will give to textual support in exams 2022-2023 to complete **exercise 2.2 maths class 10 chapter 2** in english medium. So revise and practice these all cbse study materials like class 10 maths chapter 2.2 in english ncert book. Also ensure to repractice all syllabus within time or before board exams for ncert class 10 maths ex 2.2 in english.

See all solutions for class 10 maths chapter 2 exercise 2 in english medium solved questions with answers.

### Exercise 2.2 class 10 Mathematics Chapter 2. Polynomials

## 2. Polynomials

### | Exercise 2.2 |

## Exercise 2.2 Class 10 maths 2. Polynomials - ncert solutions - Toppers Study

**Chapter 2. Polynomials**

### Exercise 2.2 Class 10 maths Chapter 2. Polynomials

**Q1. Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.**

(i) *x*^{2} – 2*x *– 8

**Solution:**

Using Middle term splitting method:

x^{2} – 4x + 2x – 8 = 0

⇒ x(x – 4) + 2(x – 4) = 0

⇒ x(x – 4) + 2(x – 4) = 0

⇒ (x – 4) (x + 2) = 0

⇒ x – 4 = 0 x + 2 = 0

⇒ x = 4, x = – 2

Zeroes; α = 4 β = – 2

Verifying the relationship between the zeroes and the coefficients.

a = 1, b = – 2, and c = – 8

(ii) 4*s*^{2} – 4*s *+ 1

(iii) 6*x*^{2} – 3 – 7*x*

(iv) 4*u*^{2} + 8*u *

(v) *t*^{2 }– 15

(vi) 3*x*^{2} – *x *– 4

**Solution:**

**(ii) 4 s^{2} – 4s + 1**

**Solution: **

4s^{2}– 4s + 1 = 0

⇒ 4s^{2} – 2s – 2s + 1 = 0

⇒ 2s (2s – 1) –1(2s – 1) = 0

⇒ (2s – 1) (2s – 1) = 0

⇒ 2s – 1= 0, 2s – 1= 0

⇒ 2s = 1, 2s = 1

Coefficients

a = 4, b = – 4, c = 1

Relationship between zeroes and coefficients

L.H.S = R.H.S

L.H.S = R.H.S

Hence verified the relationship between coefficients and the zeroes in both cases.

**(iii) 6 x^{2} – 3 – 7x**

**Solution:**

⇒ 6x^{2 }– 3 – 7x = 0

⇒ 6x^{2 }– 7x – 3 = 0 (After rearranging the equation)

⇒ 6x^{2 }– 9x + 2x – 3 = 0

⇒ 3x (2x – 3) +1 (2x – 3) = 0

⇒ (2x – 3) (3x + 1) = 0

⇒ 2x – 3 = 0, 3x + 1 = 0

⇒ 2x = 3, 3x = - 1

Hence verified the relationship between coefficients and the zeroes in both cases.

**(iv) 4 u^{2} + 8u**

**Solution:** 4u(u + 2) = 0

4u = 0, u + 2 = 0

u = 0, u = – 2

Zeroes: a = 0, b = – 2

Coefficients:

a = 4, b = 8, c = 0

Verifying relationship between zeroes and coefficients

⇒ 0 = 0

⇒ L.H.S = R.H.S

Hence verified, the relationship between coefficients and zeroes in both cases.

**(v) t^{2 }– 15**

**Solution:**

t^{2} – 15 = 0

t^{2} = 15

t = ±√15

t = √15, t = – √15

Zeroes: a = √15, b = – √15

Coefficients a = 1, b = 0, c = – 15

Verifying relationship between zeroes and Coefficients

Hence verified, the relationship between coefficients and zeroes in both cases.

**(vi) 3 x^{2} – x – 4**

**Solution:**

3*x*^{2} – *x *– 4 = 0

⇒ 3x^{2 }+ 3x – 4x – 4 = 0

⇒ 3x (x + 1) – 4 (x + 1) = 0

⇒ (x + 1) (3x – 4) = 0

⇒ x + 1 = 0, 3x – 4 = 0

⇒ x = –1 and 3x = 4

L.H.S= R.H.S

Hence verified, the relationship between coefficients and zeroes in both cases.

**Q2. . Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively.**

Hence, required quadratic polynomial is 4x^{2} – x – 4

Hence, required quadratic polynomial is 3x^{2 }–3 x + 1

Hence, required quadratic polynomial is x^{2} + √5

Hence, required quadratic polynomial is x^{2 }– x + 1

Hence, required quadratic polynomial is 4X^{2 }+ x + 1

Hence, required quadratic polynomial is x^{2} – 4 + 1

##### Other Pages of this Chapter: 2. Polynomials

### Select Your CBSE Classes

Important Study materials for classes 06, 07, 08,09,10, 11 and 12. Like CBSE Notes, Notes for Science, Notes for maths, Notes for Social Science, Notes for Accountancy, Notes for Economics, Notes for political Science, Noes for History, Notes For Bussiness Study, Physical Educations, Sample Papers, Test Papers, Mock Test Papers, Support Materials and Books.

*Mathematics Class - 11th*

NCERT Maths book for CBSE Students.

books

## Study Materials List:

##### Solutions ⇒ Class 10th ⇒ Mathematics

## Topper's Study

New Books